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Let P be a probability function on S = {X1 , X2 , X3} if P(X1)= ¼ and P(X3) = 1/3 then P (X2) is equal to
- a)5/12
- b)7/12
- c)3/4
- d)none
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Let P be a probability function on S = {X1 , X2 , X3} if P(X1)= and P...
Given information:
- S = {X1, X2, X3}
- P(X1) =
- P(X3) = 1/3
To find:
- P(X2)
Solution:
- As P is a probability function, the sum of probabilities of all elements in the sample space S must be 1.
- Therefore, P(X1) + P(X2) + P(X3) = 1
- Using the given values, we get:
+ + 1/3 = 1
+ = 2/3
- Therefore, P(X2) =
Answer:
- P(X2) =
- Option A, 5/12, is the correct answer.
- S = {X1, X2, X3}
- P(X1) =
- P(X3) = 1/3
To find:
- P(X2)
Solution:
- As P is a probability function, the sum of probabilities of all elements in the sample space S must be 1.
- Therefore, P(X1) + P(X2) + P(X3) = 1
- Using the given values, we get:
+ + 1/3 = 1
+ = 2/3
- Therefore, P(X2) =
Answer:
- P(X2) =
- Option A, 5/12, is the correct answer.
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Community Answer
Let P be a probability function on S = {X1 , X2 , X3} if P(X1)= and P...
Sum of probabilities = 1
P(X1) + P(X2) + P(X3) = 1
1/4 + 1/3 + P(X3) = 1
P(X3) = 1 - (1/4 +1/3)
P(X3) = 1 - (7/12)
P(X3) = 5/12
P(X1) + P(X2) + P(X3) = 1
1/4 + 1/3 + P(X3) = 1
P(X3) = 1 - (1/4 +1/3)
P(X3) = 1 - (7/12)
P(X3) = 5/12
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Let P be a probability function on S = {X1 , X2 , X3} if P(X1)= and P(X3) = 1/3 then P (X2) is equal toa)5/12b)7/12c)3/4d)noneCorrect answer is option 'A'. Can you explain this answer?
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